x=36x-x^2

Solution for x=36x-x^2 equation:

x=36x-x^2

We move all terms to the left:

x-(36x-x^2)=0

We get rid of parentheses

x^2-36x+x=0

We add all the numbers together, and all the variables

x^2-35x=0

a = 1; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·1·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*1}=\frac{70}{2}
=35
$